Titik pusat parabola y= x^2 +4
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Pertanyaan
Titik pusat parabola y= x^2 +4
1 Jawaban
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1. Jawaban burilhamgunawan
x^2 = y - 4
(x-0)^2 = 1(y -4)
(x -α)^2 = -4p(y -β)
α = 0
1 = -4p
p = - (1/4)
β = 4
titik puncak (α , β) = (0,4)
titik fokus (α , β-p)
titik fokus (0 , 4 + 1/4) = (0 , 17/4)