tolongin ini buat besok...fisika gan...poinnya 50 lho..

16. Diketahui
A1 = 5 cm²
A2 = 4 cm²
massa jenis = 1.000 kg/m³
h = 45 cm = 0,45 m
g = 10 m/s²

v = A2√[(2gh) : (A1² − A2²)]
v = 4√[(2×10×0,45) : (5² - 4²)]
v = 4√[(20×0,45) : (25 - 16)]
v = 4√[(9)/(9)
v = 4√1
v = 4 m/s

17.
Diketahui
jarak lubang ke tanah (H) = 9 m
jarak lubang ke permukaan (h) = 4 m

Jarak mendatar keluarnya air
[tex] = 2 \sqrt{9 \times 4} \\ = 2 \sqrt{36} \\ = 2 \times 6 \\ = 12 \: m[/tex]
E. 12 m

18)
A. 1) 2) dan 3)

19.
m es = 900 gram
T es = -10° C
C es = 0,5 kal/gram°C
L es = 80 kal/gram
T air = 20° C

Q total
m×c es×(0-T es)+(m×L)+(m×c air×(T air - 0)
= 900×0,5×(0-(-10))+(900×80)+(900×1×(20-0))
= (450×10)+(72.000)+(900×20)
= 4.500 + 72.000 + 18.000
= 4.500 + 90.000
= 94.500

20.
Diketahui
m es = 50 gram
T es = 0° C
L es = 80 kal/gram
m air = 200 gram
T air = 30° C
c air = 1 kal/gram

Q lepas = Q terima
(m×c×(T air-Tc))air = (m × L)es + (m × c × (Tc - T))
200 × 1 × (30 - Tc) = 50 × 80 + 50 × 1 × (Tc - 0)
200(30 - Tc) = 4.000 + 50(Tc)
6.000 - 200Tc = 4.000 + 50Tc
6.000 - 4.000 = 50Tc + 200Tc
2.000 = 250Tc
Tc = 8°C

B. 8°C