jika pq=15 cm dan ps=9 cm, maka panjang rs=? tolong dijawab kak

[tex] {pq}^{2} = ps \times pr \\ {15}^{2} = 9 \times (9 + sr) \\ 225 = 81 \times 9sr \\ 9sr = 225 - 81 \\ 9sr = 144 \\ sr = \frac{144}{9} \\ = 16 \\ \\ selesai[/tex]