Buktikan 1.lim (2x^2-3x-2 per x-2) =5 Q mendekati 2 2.lim (5x+2) = -3 Q mendekati 1

1)/lim (2x^2 -3x -2)/(x-2) = 5.( x=>2)
= (2.2^2 -.3.2-2)/(2-2)
= (8-6-2)/0 = 0/0
= lim { (2x +1)(x-2) }/(x-2)
= lim (2x +1)
untuk x =>2 = (2.2+1) = 4+1= 5
2) soal no 2 mungkin
lim (5x +2) = -3 , untuk x => -1
= { 5.(-1)+2 }
= -5 +2
= -3