Diketahui garis y= 2× - 5 dan 3y -9× +6=0 maka titik potong kedua garis adalah

Kelas 8 Matematika
Bab SPLDV

3y - 9x + 6 = 0
3(2x - 5) - 9x + 6 = 0
6x - 15 - 9x + 6 = 0
-3x = 9
x = 9/-3
x = -3

y = 2x - 5
y = 2 . (-3) - 5
y = -6 - 5
y = -11

Titik potong = (-3, -11)

y = 2x - 5
y - 2x = - 5

3y - 9x + 6 = 0
3y - 9x = - 6

y - 2x = - 5 |×3
3y - 9x = - 6
maka
3y - 6x = - 15
3y - 9x = - 6
-------------------(-)
3x = - 9
x = - 3

subtitusi
y - 2x = - 5
y - 2(-3) = - 5
y + 6 = - 5
y = - 5 - 6
y = - 11

ttk potong = ( - 3, - 11 )