Titik p=(a,2) dan q=(3,b) terletak pada garis 3x-7y=26, nilai a+b adalah...

(x,y) = (a,2)
3(a) - 7(2) = 26
3a - 14 = 26
3a = 26 + 14
a = 40/3
(x,y) = (3,b)
3(3) - 7b = 26
9 - 7b = 26
-7b = 26 - 9
b = 17/-7

a + b = 40/3 - 17/7
= 280/21 - 51/21
= 229/21

Titik p = (a,2) terletak pada 3x-7y=26, maka
3a - 7(2) = 26
3a = 26 + 14
3a = 40
a = 40/3

Titik q = (3,b) terletak pada 3x-7y=26, maka
3(3) - 7b = 26
7b = 9 - 26
7b = -17
b = -17/7

a + b
= 40/3 - 17/7
= (280 - 51)/21
= 229/21