langkah langkah di jelaskan

2log (3x^2 +5x +6)- 2log (3x +1) = 2.
2log { (3x^3 +5x +6)/(3x+1) } = 2log 2^2
(3x^2 +5x +6)/(3x+1) = 2^2
3x^2 +5x +6 = 12x + 4
3x^2 +5x +6 -12x - 4 = 0
3x^2 -7x +2 = 0
(3x -1)(x -2) = 0
x1 = 1/3 atau x2 = 2
maka a = 2 dan b = 1/3.
a - b = 2 - 1/3 = 5/3 = 1 2/3
a.b = 2.1/3 = 2/3