pada lemparan dua buah dadu 48 kali frekuensi muncul sadu berumlah 7 adalah

Dua buah dadu
S{(1,1)(1,2)(1,3)(1,4)(1,5)(1,6)(2,1)(2,2)(2,3)(2,4)(2,5)(2,6)(3,1)(3,2)(3,3)(3,4)(3,5)(3,6)(4,1)(4,2)(4,3)(4,4)(4,5)(4,6)(5,1)(5,2)(5,3)(5,4)(5,5)(5,6)(6,1)(6,2)(6,3)(6,4)(6,5)(6,6)}
n(S)=36
n=48 kali
A=peluang muncul mata dadu berjumlah 7
A={(1,6)(2,5)(3,4)(4,3)(5,2)(6,1)}
n(A)=6
P(A)=n(A)/n(S)
=6/36
=1/6

Frekuensi harapan A
=n×P(A)
=48×1/6
=8 kali

Semoga bisa membantu...