Himpunan penyelesaian dari |2x-4|^2+4|2x-4|=12 adalah

|2x-4|² + 4|2x-4| - 12 = 0
(|2x-4| - 2)(|2x-4| + 6) = 0
|2x-4| - 2 = 0 dan |2x-4| + 6 = 0
|2x-4| - 2 = 0
|2x-4| = 2
2x - 4 = 2
2x = 6
x = 3
atau
2x - 4 = -2
2x = 2
x = 1
|2x - 4| + 6 = 0
|2x - 4| = -6
2x - 4 = -6
2x = -2
x = -1
2x - 4 = 6
2x = 10
x = 5
hp {-1, 1, 3, 5}