[Logaritma] Jika f(x^2 + 3x + 1) = ^2log(2x^3 - x^2 + 7) , x ≥ 0 Dit : Maka f(5) ?

Kelas 10 Matematika
Bab Logaritma

^ = pangkat

x² + 3x + 1 = 5
x² + 3x + 1 - 5 = 0
x² + 3x - 4 = 0
(x + 4) (x - 1) = 0
x + 4 = 0
x = -4

x - 1 = 0
x = 1

x >= 0

²log (2x^3 - x² + 7)
= ²log (2 . 1^3 - 1² + 7)
= ²log (2 - 1 + 7)
= ²log 8
= ²log 2^3
= 3 . ²log 2
= 3

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