persamaan garis melalui yang titik A(5,4) dan B(10,8)

[tex]x_{1}=5; y_{1}=4 \\ x_{2}=10; y_{2}=8 \\ \\ \frac{y-y_{1}}{y_{2}-y_{1}}= \frac{x-x_{1}}{x_{2}-x_{1}} \\ \\ \frac{y-4}{8-4} = \frac{x-5}{10-5} \\ \\ \frac{y-4}{4} = \frac{x-5}{5} \\ \\ 5(y-4)=4(x-5) \\ 5y-4=4x-5 \\ 5y=4x+4-5 \\ 5y=4x-1 \\ 5y-4x=-1 \\ 5y-4x+1=0[/tex]