tolong bantu pake cara soalny udh deadline

Syarat 1 =
[tex]2 {x}^{2} - 3x - 9 \geqslant 0 \\ (2x + 3)(x - 3) \geqslant 0 \\ x = - \frac{3}{2} \: \: \: \: \: \: x = 3[/tex]
Syarat 2 =
[tex]9 - {x}^{2} \geqslant 0 \\ (3 + x)(3 - x) \geqslant 0 \\ x = - 3 \: \: \: \: \: x = 3[/tex]
Syarat 3 =
[tex]( \sqrt{2 {x}^{2} - 3x - 9 } )^{2} < (\sqrt{9 - {x}^{2} } )^{2} \\ 2 {x}^{2} - 3x - 9 < 9 - {x}^{2} \\ 3 {x}^{2} - 3x - 18 < 0 \\ (3x - 9)(x + 2) < 0 \\ x = 3 \: \: \: \: \: x = - 2[/tex]
Buat garis bilangan, dapet jadi :
[tex] - 2 < x \leqslant - \frac{3}{2} [/tex]