plis dijawab.... yang udah jawab trima kasih

2x + 3y = 12 dikali 3
3x + 2y = 8 dikali 2

6x + 9y = 36
6x + 4y = 16
------------------ -
5y = 20
a=y = 4

6x + 4y = 16
6x + 4(4) = 16
6× = 0
b =× = 0

a+b = 4+0 = 4 (d)

*cara eliminasi
2x + 3y = 12 | x3
3x + 2y = 8 | x2

6x + 9y = 36
6x + 4y = 16
___________ -
5y = 20
y = 4 = b

*cara subtitusi
3x + 2y = 8
3x + 2(4) = 8
3x + 8 = 8
3x = 8 - 8
3x = 0
X = 0 = a

a + b = 0 + 4 = 4 (d)