Matematika

Pertanyaan

tolong ya mat .........
tolong ya mat .........

2 Jawaban

  • No. 17
    y + 3 = (1/2) (x + 2)
    y + 3 = x/2 + 1
    y = x/2 + 1 - 3
    y = x/2 - 2
    2y = x - 4
    2y - x + 4 = 0

    no. 18
    Eliminasi
    -3x + 2y = 8
    4x - 2y = -20
    ------------------ (+)
    x = -12

    sbtitusi
    2x - y = -10
    2(-12) - y = -10
    y = -24 + 10
    y = -14

    jadi inilai 
    a - 2b
    = -12 - 2(-14)
    = -12 + 28
    = 16

  • Soal No. 17
    [tex]y-y_{1}=m.(x-x_{1}) \\ \\ y-(-3)= \frac{1}{2}.(x-(-2)) \\ \\ y+3= \frac{1}{2}.(x+2) \\ \\y+3= \frac{1}{2}x+1 \\ \\ 2y+6=x+2 \\ 2y-x+6-2=0 \\ 2y-x+4=0 [/tex]
    Jawaban (B)

    Soal No. 18
    x = a
    y = b
    - 3a + 2b = 8 .......(× 1) ⇒ - 3a + 2b = 8
      2a -    b = - 10....(× 2) ⇒   4a  - 2b = - 20
                                               ---------------------(+)
                                                              a = - 12

    2a - b = - 10
    2.(-12) - b = - 10
    - 24 - b = - 10..........dikali (-1)
    24 + b = 10
    b = 10 - 24
    b = - 14

    a - 2b = (-12) - 2(-14)
               = (-12) - (-28)
               = -12 + 28
    a - 2b = 16..................Jawaban (A)