persamaan garis yang melalui titik (-2 , 3) dan ( 1, 1 ) adalah ...

Jawab :

m = y2 - y1/ x2 - x1 = 1 - 3/ 1-(-2) = -2/3

y - y1 = m(x - x1)
y - 3 = - 2/3(x - (-2))
y - 3 = - 2/3(x + 2)
y - 3 = - 2/3 + 2/3 × 2
y - 3 = - 2/3 + 4/3
________________ × 3
3. y - 3 . 3 = - 2/3 . 3 + 4/3 . 3

3y - 9x = -2 + 4
3y - 9x + 2 - 4 = 0
3y + 2x - 13 = 0
2x + 3y - 13 = 0