Tentukan persamaan linear 1 variabel 1.2(x + 3) = -4 - 3x 2. X - 1/2 = 2x + 4 ¼ 3. 4 (2x × 3 1/2) = 3 (½x - 4)

1. 2x+6=-4-3x
2x+3x=-4-6
5x = -10
x = -2
2. X- 1/2=2x+4¼
x-2x = 1/2+17/4
-x = 2/4+17/4
-x = 19/4
x =
[tex] - \frac{19}{4} [/tex]
3. 4(2x×3 ½)=3(½x-4)
aku lupaaa maaf :)