Jika f(x) =x^+2x-3, g(x)=x-2 dan h(x)=2x-1 komposisi fungsi (fogoh)(x) ....

jawab

f(x) = x² + 2x - 3
g(x) = x - 2
h(x) = 2x - 1


{ fogoh }(x) = f { goh(x)} 
= f { g(2x - 1) }
= f  { (2x - 1) - 2}
= f { 2x  - 3 }
= (2x - 3)² + 2 (2x - 3)  - 3
= 4x² - 12x + 9 + 4x - 6 - 3
= 4x² - 8x