Dua buah dadu ditos bersama-sama. Tentukanlah peluang dari: a. muncul mata dadu yang jumlahnya merupakan bilangan perima, b. muncul mata dadu berjumlah lebih da

Dua buah dadu
S={(1,1)(1,2)(1,3)(1,4)(1,5)(1,6)(2,1)(2,2)(2,3)(2,4)(2,5)(2,6)(3,1)(3,2)(3,3)(3,4)(3,5)(3,6)(4,1)(4,2)(4,3)(4,4)(4,5)(4,6)(5,1)(5,2)(5,3)(5,4)(5,5)(5,6)(6,1)(6,2)(6,3)(6,4)(6,5)(6,6)}
n(S)=36
a.
A=peluang muncul mata dadu jumlahnya bilangan prima
={(1,1)(1,2)(1,4)(1,6)(2,1)(2,3)(2,5)(3,2)(3,4)(4,1)(4,3)(5,2)(5,6)(6,1)(6,5)}
n(A)=15
P(A)=n(A)/n(S)
=15/36
=5/12
b.
B=peluang muncul mata dadu berjumlah lebih dari 6
={(1,6)(2,5)(2,6)(3,4)(3,5)(3,6)(4,3)(4,4)(4,5)(4,6)(5,2)(5,3)(5,4)(5,5)(5,6)(6,1)(6,2)(6,3)(6,4)(6,5)(6,6)}
n(B)=21
P(B)=n(B)/n(S)
=21/36
=7/12
c.
C=peluang muncul mata dadu pertama dan kedua sama
={(1,1)(2,2)(3,3)(4,4)(5,5)(6,6)}
n(C)=6
P(C)=n(C)/n(S)
=6/36
=1/6

Semoga bisa membantu...

a.
A = {(1,1), (1,2),(1,4),(1,6), (2,1),(2,3),(2,5),(3,2),(3,4),(4,1),(4,3),(5,2),(5,6), (6,1),(6,5)}
n(A) = 15
n (s) = 36
P = 15/36 = 5/12

b.
A = {(1,6),(2,5),(2,6),(3,4),(3,5),(3,6),(4,3),(4,4),(4,5),(4,6),(5,2),(5,3)(,5,4),(5,5),(5,6),(6,1),(6,2),(6,3)(6,4),(6,5),(6,6)}
n(A) = 21
n(s) = 36

P = 21/36 = 7/12

c.
A = {(1,1),(2,2)(3,3),(4,4),(5,5),(6,6)}
n(A) = 6
n(s) = 36

P = 6/36 = 1/6