Diketahui g(×) =a× + b,jika g (-2) =-4 dan g (-6) =12 ,maka nilai g (1)=

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g(x) = ax + b
g(-2) = -2a+ b
-4 = -2a + b
b = 2a - 4

g(-6) = a(-6) + b
12 = -6a + (2a) -4
12 = -4a - 4
4a = - 12 -4
4a = -16
a = -16/4
a = -4

b = 2a - 4
b = 2(-4) - 4
b = -8 - 4
b = -12

g(1) = ax + b
= -4(1) + (-12)
= -4+(-12)
g(1) = -16